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Trigo Proving Question (O Level) Step-by-Step

Source: TRIGO PROVING O Level 2025, Paper 1

Introduction

Many students lose marks in a trigo proving question because they expand too quickly or mix up identities. The good news: most O Level proofs become easy when you simplify one side carefully and use the right identity at the right time.

In this guide, we’ll break down this trigo proving question in a clean, exam-ready way.

 

trigo proving question showing equals cosecθ

 

The Question / Scenario Explanation

Source: TRIGO PROVING O Level 2025, Paper 1

Prove that

\(\frac{1 + \sin 2\theta}{\sin \theta} – \frac{1 + \cos 2\theta}{\cos \theta} = \cosec \theta\)

 

Step-by-Step Solution / Explanation

Step 1: Use double-angle identities

For this trigo proving question, use:

  • \(\sin 2\theta = 2\sin \theta \cos \theta\)
  • \(\cos 2\theta = 2\cos^2 \theta – 1\) (this form is very useful here)

Start with the LHS:

\(\frac{1 + \sin 2\theta}{\sin \theta} – \frac{1 + \cos 2\theta}{\cos \theta}\)

Substitute:

\(\frac{1 + 2\sin \theta \cos \theta}{\sin \theta} – \frac{1 + (2\cos^2 \theta – 1)}{\cos \theta}\)

Step 2: Simplify each fraction separately

First fraction:

\(\frac{1}{\sin \theta} + \frac{2\sin \theta \cos \theta}{\sin \theta} = \cosec \theta + 2\cos \theta\)

Second fraction:

\(\frac{2\cos^2 \theta}{\cos \theta} = 2\cos \theta\)

Step 3: Finish the proof

Now subtract:

\((\cosec \theta + 2\cos \theta) – (2\cos \theta) = \cosec \theta\)

So the expression equals the RHS:

\(\frac{1 + \sin 2\theta}{\sin \theta} – \frac{1 + \cos 2\theta}{\cos \theta} = \cosec \theta\)

Proved. This trigo proving question simplifies neatly once the correct identity form is chosen.

 

Key Concepts Students Must Know

  • Double-angle identity: \(\sin 2\theta = 2\sin \theta \cos \theta\)
  • Useful double-angle form: \(\cos 2\theta = 2\cos^2 \theta – 1\)
  • Basic conversion: \(\cosec \theta = \frac{1}{\sin \theta}\)
  • Good habit for any trigo proving question: simplify one side (usually LHS) until it matches the RHS

 

Exam Tips / Common Mistakes

Exam Tips

  • Pick the identity form that cancels nicely (here, \(\cos 2\theta = 2\cos^2 \theta – 1\) makes the second fraction clean).
  • Simplify fraction-by-fraction before expanding everything.
  • Always rewrite \(\frac{1}{\sin \theta}\) as \(\cosec \theta\) near the end so the RHS becomes obvious.

Common Mistakes

  • Using \(\cos 2\theta = 1 – 2\sin^2 \theta\) here can make the algebra longer.
  • Forgetting to split: \(\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}\) (this is what reveals \(\cosec \theta\)).
  • Cancelling incorrectly: \(\frac{2\sin \theta \cos \theta}{\sin \theta} = 2\cos \theta\) (only \(\sin \theta\) cancels).

 

Parent Insight

Trigonometry proofs look intimidating, but they are pattern-based. When students practise 10–20 proofs with the same structure, they start recognising which identities to use quickly. That speed and confidence matters a lot in O Level Paper 1.

 

Conclusion

This trigo proving question is best solved by substituting \(\sin 2\theta\) and using the smart form \(\cos 2\theta = 2\cos^2 \theta – 1\). After splitting and cancelling carefully, the expression becomes \(\cosec \theta\), which matches the RHS exactly.

 

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Frequently Asked Questions
Usually start from the more complex side (often the LHS) and simplify step-by-step until it matches the RHS.
Choose the form that simplifies your denominators fastest: If denominator is \(\cos \theta\), then \(\cos 2\theta = 2\cos^2 \theta – 1\) is often best. If denominator is \(\sin \theta\), then \(\cos 2\theta = 1 – 2\sin^2 \theta\) may be better.

When your simplified expression matches the RHS exactly (including the same trig function name, like \(\csc \theta\)), you can write “Hence proved”.