Additional Maths Tuition

O-Level A-Maths 2021 Paper 1 Q4 – Integration Using Basic Rules

Source: O-Level Additional Mathematics 2021 Paper 1 Question 4

Introduction

This O-Level A-Maths question tests your understanding of:

  • splitting integrals
  • applying the power rule
  • integrating expressions of the form \(\dfrac{1}{ax+b}\)

It is a fundamental integration question that students must score confidently in Paper 1.
We follow the teacher’s exact board working.

 

The Question

Evaluate:

\(\int \left(\dfrac{3}{x^2} + \dfrac{4}{3x – 5}\right) dx\)

 

Step-by-Step Working (Teacher’s Method)

Step 1: Split the integral

\(\int \dfrac{3}{x^2}\, dx + \int \dfrac{4}{3x – 5}\, dx\)

Step 2: Integrate the first term

Rewrite:

\(\dfrac{3}{x^2} = 3x^{-2}\)

Apply the power rule:

\(\int 3x^{-2}\, dx = 3 \cdot \dfrac{x^{-1}}{-1} = -\dfrac{3}{x}\)

Step 3: Integrate the second term

Let:

\(u = 3x – 5 \quad \Rightarrow \quad du = 3dx\)

So:

\(\int \dfrac{4}{3x – 5}\, dx = \dfrac{4}{3} \ln|3x – 5|\)

Step 4: Combine the results

\(-\dfrac{3}{x} + \dfrac{4}{3}\ln|3x – 5| + C\)

 

✅ Final Answer

\(\int \left(\dfrac{3}{x^2} + \dfrac{4}{3x – 5}\right) dx = -\dfrac{3}{x} + \dfrac{4}{3}\ln|3x – 5| + C\)

 

Key Concepts

ConceptWhy It Matters
Splitting integralsMakes integration manageable
Power ruleUsed for \(x^n\)
Logarithmic integrationRequired for \(\dfrac{1}{ax+b}\)
Constant of integrationMust always be included

 

Tips for Students

  • Split integrals early
  • Rewrite using index notation
  • Watch negative powers carefully
  • Always include + C

 

For Parents

Integration is a core A-Maths skill that builds:

  • algebra confidence
  • calculus fluency
  • exam speed

Mastering these basics ensures strong performance in O-Level A-Maths Paper 1.

 

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Frequently Asked Questions

It simplifies the calculation and reduces errors.

\(\int \dfrac{1}{ax+b}\, dx = \dfrac{1}{a}\ln|ax+b| + C\)

We use ln whenever the integrand is of the form \(\dfrac{1}{ax+b}\). This comes directly from the rule for integrating reciprocal linear expressions.

Yes — it results in lost marks.